LeetCode:14. 最长公共前缀

tech2024-01-08  107

编写一个函数来查找字符串数组中的最长公共前缀。

如果不存在公共前缀,返回空字符串 “”。

示例 1:

输入: [“flower”,“flow”,“flight”] 输出: “fl”

示例 2:

输入: [“dog”,“racecar”,“car”] 输出: “” 解释: 输入不存在公共前缀。

说明: 所有输入只包含小写字母 a-z 。 Java实现:

//方法一:横向扫描 class Solution { public String longestCommonPrefix(String[] strs) { if (strs == null || strs.length == 0) { return ""; } String prefix = strs[0]; int count = strs.length; for (int i = 1; i < count; i++) { prefix = longestCommonPrefix(prefix, strs[i]); if (prefix.length() == 0) { break; } } return prefix; } public String longestCommonPrefix(String str1, String str2) { int length = Math.min(str1.length(), str2.length()); int index = 0; while (index < length && str1.charAt(index) == str2.charAt(index)) { index++; } return str1.substring(0, index); } } //方法二:纵向扫描 class Solution { public String longestCommonPrefix(String[] strs) { if (strs == null || strs.length == 0) { return ""; } int length = strs[0].length(); int count = strs.length; for (int i = 0; i < length; i++) { char c = strs[0].charAt(i); for (int j = 1; j < count; j++) { if (i == strs[j].length() || strs[j].charAt(i) != c) { return strs[0].substring(0, i); } } } return strs[0]; } } //方法三:分治 class Solution { public String longestCommonPrefix(String[] strs) { if (strs == null || strs.length == 0) { return ""; } else { return longestCommonPrefix(strs, 0, strs.length - 1); } } public String longestCommonPrefix(String[] strs, int start, int end) { if (start == end) { return strs[start]; } else { int mid = (end - start) / 2 + start; String lcpLeft = longestCommonPrefix(strs, start, mid); String lcpRight = longestCommonPrefix(strs, mid + 1, end); return commonPrefix(lcpLeft, lcpRight); } } public String commonPrefix(String lcpLeft, String lcpRight) { int minLength = Math.min(lcpLeft.length(), lcpRight.length()); for (int i = 0; i < minLength; i++) { if (lcpLeft.charAt(i) != lcpRight.charAt(i)) { return lcpLeft.substring(0, i); } } return lcpLeft.substring(0, minLength); } } //方法四:二分查找 class Solution { public String longestCommonPrefix(String[] strs) { if (strs == null || strs.length == 0) { return ""; } int minLength = Integer.MAX_VALUE; for (String str : strs) { minLength = Math.min(minLength, str.length()); } int low = 0, high = minLength; while (low < high) { int mid = (high - low + 1) / 2 + low; if (isCommonPrefix(strs, mid)) { low = mid; } else { high = mid - 1; } } return strs[0].substring(0, low); } public boolean isCommonPrefix(String[] strs, int length) { String str0 = strs[0].substring(0, length); int count = strs.length; for (int i = 1; i < count; i++) { String str = strs[i]; for (int j = 0; j < length; j++) { if (str0.charAt(j) != str.charAt(j)) { return false; } } } public class MainClass { public static String[] stringToStringArray(String input) { JsonArray jsonArray = JsonArray.readFrom(line); String[] arr = new String[jsonArray.size()]; for (int i = 0; i < arr.length; i++) { arr[i] = jsonArray.get(i).asString(); } return arr; } public static void main(String[] args) throws IOException { BufferedReader in = new BufferedReader(new InputStreamReader(System.in)); String line; while ((line = in.readLine()) != null) { String[] strs = stringToStringArray(line); String ret = new Solution().longestCommonPrefix(strs); String out = (ret); System.out.print(out); } } }
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