在时间差额和费用的计算上有些问题，既繁琐还容易出错，可以参考柳婼PAT1016，也算是为以后类似的计算提供了一种通法
#pragma warning(disable:4996) #include<stdio.h> #include<cstring> #include<algorithm> #include<iostream> using namespace std; struct information { char name[22]; int MM, dd, hh, mm; char line[10]; }info[1010]; bool cmp(struct information a, struct information b) { int s = strcmp(a.name, b.name); if (s != 0) return s < 0; if (a.MM != b.MM) return a.MM < b.MM; else if (a.dd != b.dd) return a.dd < b.dd; else if (a.hh != b.hh) return a.hh < b.hh; else return a.mm < b.mm; } int havecout = 0; double personsum = 0; int main() { int fee[24], daysum = 0; for (int i = 0; i < 24; i++) { scanf("%d", &fee[i]); daysum = daysum + fee[i]; } int N; scanf("%d", &N); for (int i = 0; i < N; i++) { scanf("%s %d:%d:%d:%d %s", info[i].name, &info[i].MM, &info[i].dd, &info[i].hh, &info[i].mm, info[i].line); } sort(info, info + N, cmp); char on[10] = { "on-line" }; char off[10] = { "off-line" }; for (int i = 0; i < N - 1; i++) { if (strcmp(on, info[i].line) == 0) { if (strcmp(info[i + 1].name, info[i].name) == 0 && (strcmp(off, info[i + 1].line) == 0)) { if (havecout == 0) { printf("%s %02d\n", info[i + 1].name, info[i + 1].MM); havecout++; } printf("%02d:%02d:%02d ", info[i].dd, info[i].hh, info[i].mm); printf("%02d:%02d:%02d ", info[i + 1].dd, info[i + 1].hh, info[i + 1].mm); double sum = 0; int time = 0; sum = (info[i + 1].dd - info[i].dd)*daysum*60; time = (info[i + 1].dd - info[i].dd) * 24 * 60; sum = sum + fee[info[i].hh] * (60 - info[i].mm) + fee[info[i + 1].hh] * info[i + 1].mm; time = time + 60 - info[i].mm + info[i + 1].mm; if (info[i].hh == info[i + 1].hh) { time = time - 60; sum = sum - 60 * fee[info[i].hh]; } for (int j = info[i].hh + 1; j < info[i + 1].hh; j++) { sum = sum + fee[j] * 60; time = time + 60; } printf("%d $%.2f\n", time, sum / 100); personsum = personsum + sum / 100; int flag = 1; for (int j = i + 2; j < N - 1; j++) { if (strcmp(info[i].name, info[j+1].name) == 0) if (strcmp(info[j].line, on) == 0 && strcmp(info[j + 1].line, off) == 0) { flag = 0; break; } if (strcmp(info[i].name, info[j + 1].name) != 0) { break; } } if (flag==1) { havecout = 0; printf("Total amount: $%.2f\n", personsum); personsum = 0; } } } } }