Python 将字节类型转换为“十六进制“字符串

tech2025-05-23  7

s='FD' print(s.encode().hex()) #4644

 

s="FD FD 30 03 79 E3 00 34 64 00 C0 00 43 00 1B 00 15 00 1B 00 00 00 15 00 FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF FF 01 12 22 12 21 12 12 21 12 11 22 12 21 22 22 22 22 22 22 22 22 21 22 12 21 11 22 22 21 11 12 22 22 22 22 21 22 22 22 22 22 22 22 22 22 22 22 22 22 22 22 22 21 11 12 22 13 F0 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 05 76 00 F9 DF DF" s2=s.strip().split(' ') #字符串去除首尾空格后,再分割空格转成数组 m=0 for j in s2: print(j.encode().hex()+",",end="") #转化为16进制字符串 m+=1 if m%10==0: print("\n",end="") #每打印十行输出换行符 print("\n") print(len(s2))#数组长度

 

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