c# jobject 数据结构的解析： 首先下载Newtonsoft.Json，增加引用using Newtonsoft.Json.Linq; 把jobject的内容提取出来，Jobject的内容格式如下:

 

{  "code": 200,  "msg": "SUCCESS",  "data": {   "id": "12345678",   "name": "张三",   "sex": "男",   "result": {    "access_token": "49d58eacd7811e463429a1ae10b42173",    "user_info": [{     "school": "社会大学",     "major": "软件开发",     "education": "本科",     "score": 97    }, {     "school": "湖南大学",     "major": "软件工程",     "education": "研究生",     "score": 100    }]   }  } }

可放到json官网在线JSON校验格式化工具里解析。

 

代码如下：                   

1，新建类：         public class UserInfo         {             public string id { get; set; }             public string name { get; set; }             public string sex { get; set; }             public string access_token { get; set; }             public string school { get; set; }             public string major { get; set; }             public string education { get; set; }             public string score { get; set; }         }

2，获取值：

            JObject result = new JObject();//假设result为数据结构             UserInfo userinfo = new UserInfo();             userinfo.id = result["data"].Value<string>("id");//id             userinfo.name = result["data"].Value<string>("name"); //name             userinfo.sex = result["data"].Value<string>("sex"); //sex             userinfo.access_token= result["data"]["result"]["access_token"].ToString();//access_token             JArray res = result["data"]["result"].Value<JArray>("user_info");             JObject obj = JObject.Parse(res[0].ToString());//只获取数据结构中第一个userinfo里的数据信息             userinfo.school = obj.Value<string>("school"); //schoool             userinfo.major = obj.Value<string>("major");//major             userinfo.education = obj.Value<string>("education");//education             userinfo.score= obj.Value<string>("score");//score