You are given an array a1,a2,…,an, which is sorted in non-decreasing order (ai≤ai+1).
Find three indices i, j, k such that 1≤i<j<k≤n and it is impossible to construct a non-degenerate triangle (a triangle with nonzero area) having sides equal to ai, aj and ak (for example it is possible to construct a non-degenerate triangle with sides 3, 4 and 5 but impossible with sides 3, 4 and 7). If it is impossible to find such triple, report it.
Input The first line contains one integer t (1≤t≤1000) — the number of test cases.
The first line of each test case contains one integer n (3≤n≤5⋅104) — the length of the array a.
The second line of each test case contains n integers a1,a2,…,an (1≤ai≤109; ai−1≤ai) — the array a.
It is guaranteed that the sum of n over all test cases does not exceed 105.
Output For each test case print the answer to it in one line.
If there is a triple of indices i, j, k (i<j<k) such that it is impossible to construct a non-degenerate triangle having sides equal to ai, aj and ak, print that three indices in ascending order. If there are multiple answers, print any of them.
Otherwise, print -1.
Example Input 3 7 4 6 11 11 15 18 20 4 10 10 10 11 3 1 1 1000000000 Output 2 3 6 -1 1 2 3 Note In the first test case it is impossible with sides 6, 11 and 18. Note, that this is not the only correct answer.
In the second test case you always can construct a non-degenerate triangle. 思维题
#include<stdio.h> #include<string.h> #include<math.h> #include<map> #include<stack> #include<set> #include<queue> #include<vector> #include<stdlib.h> #include<iostream> #include<algorithm> #include<cstring> #include<cstdio> #include<cstdlib> #define inf 0x3f3f3f3f typedef long long ll; using namespace std; const int maxn=5e4+5; int a[maxn],b[maxn]; int main() { int n,m; cin>>n; while(n--){ cin>>m; for(int i=1;i<=m;i++) cin>>a[i]; if(a[1]+a[2]>a[m]) cout<<"-1"<<endl; else{ cout<<1<<" "<<2<<" "<<m<<endl; } } return 0; }