Math-tricks

tech2022-07-12  168

其中 x x x是复数,直接当作一阶的多元函数泰勒展开 f ( x , r ) ≥ f ( x 0 , r 0 ) + D T f ( x 0 , r 0 ) ( [ x ; r ] − [ x 0 ; r 0 ] ) f(x,r)\geq f(x_0,r_0) +D^T f(x_0,r_0) ( [x; r]-[x_0;r_0]) f(x,r)f(x0,r0)+DTf(x0,r0)([x;r][x0;r0]) 其中: D T f ( x 0 , r 0 ) = [ 2 x 0 r 0 , − x 0 2 r 0 2 ] D^T f(x_0,r_0) = [ \frac{2x_0}{r_0}, \frac{-x_0^2}{r_0^2} ] DTf(x0,r0)=[r02x0,r02x02]

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