数数字(Digit Counting,ACMICPC Danang 2007,UVa1225)

tech2022-12-07  92

#include<iostream> using namespace std; int main(){ int n; int i,j; int array[10] = {0}; cin>>n; for(i = 1;i <= n;i++){ j = i; while(j){ array[j % 10]++; j /= 10; } } for(i = 0;i < 10;i++){ cout<<array[i]<<'\t'; } return 0; }
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