实例
>>> id_num #身份证号的分组 '144731199209096719' >>> a = re.search("([0-9]{3})([0-9]{3})([0-9]{4})",id_num) >>> a.group() #输出匹配结果 '1447311992' >>> a <re.Match object; span=(0, 10), match='1447311992'> >>> a.groups() # 元组形式输出 ('144', '731', '1992') >>> a.groupdict() {}
>>> a = re.search("(?P<name>[0-9]{3})(?P<city>[0-9]{3})(?P<birthday>[0-9]{4})",id_num) >>> a.groupdict() # 字典形式输出 {'name': '144', 'city': '731', 'birthday': '1992'} >>>
