PTAThe Black Hole of Numbers (20分)

tech2023-01-12  115

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For any 4-digit integer except the ones with all the digits being the same, if we sort the digits in non-increasing order first, and then in non-decreasing order, a new number can be obtained by taking the second number from the first one. Repeat in this manner we will soon end up at the number 6174 -- the black hole of 4-digit numbers. This number is named Kaprekar Constant.

For example, start from 6767, we'll get:

7766 - 6677 = 1089 9810 - 0189 = 9621 9621 - 1269 = 8352 8532 - 2358 = 6174 7641 - 1467 = 6174 ... ...

Given any 4-digit number, you are supposed to illustrate the way it gets into the black hole.

Input Specification:

Each input file contains one test case which gives a positive integer N in the range (0,10​4​​).

Output Specification:

If all the 4 digits of N are the same, print in one line the equation N - N = 0000. Else print each step of calculation in a line until 6174 comes out as the difference. All the numbers must be printed as 4-digit numbers.

Sample Input 1:

6767

Sample Output 1:

7766 - 6677 = 1089 9810 - 0189 = 9621 9621 - 1269 = 8352 8532 - 2358 = 6174

Sample Input 2:

2222

Sample Output 2:

2222 - 2222 = 0000 #include <iostream> #include <cstdio> #include <algorithm> #include <string> #include <cstring> #include <cstdlib> #include <cmath> #include <stack> #include <queue> #include <set> #include <map> #include <vector> #include <ctime> #include <cctype> #include <bitset> #include <utility> #include <sstream> #include <complex> #include <iomanip> #include<climits>//INT_MAX #define PP pair<ll,int> #define inf 0x3f3f3f3f #define llinf 0x3f3f3f3f3f3f3f3fll #define dinf 1000000000000.0 #define PI 3.1415926 typedef long long ll; using namespace std; int const mod=1e9+7; const int maxn=3e5+10; char S[6]; bool cmp(char a,char b){ return a>b; } int main() { int n,jg; scanf("%s",S); do{ while(strlen(S)<4) S[strlen(S)]='0'; S[4]='\0'; sort(S,S+4); int mi=atoi(S); sort(S,S+4,cmp); int mx=atoi(S); jg=mx-mi; printf("%04d - %04d = %04d\n",mx,mi,jg); sprintf(S,"%d",jg); if(jg==0) return 0; }while(jg!=6174); return 0; }

 

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